How about ANY FINITE SEQUENCE AT ALL?

    • cosecantphi [he/him, they/them]@hexbear.net
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      2 days ago

      It’s implicitly defined here by its decimal form:

      0.101001000100001000001 . . .

      The definition of this number is that the number of 0s after each 1 is given by the total previous number of 1s in the sequence. That’s why it can’t contain 2 despite being infinite and non-repeating.

        • cosecantphi [he/him, they/them]@hexbear.net
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          20 hours ago

          That’s a decimal approximation of Pi with an ellipsis at the end to indicate its an approximation, not a definition. The way the ellipsis is used above is different. It’s being used to define a number via the decimal expansion by saying it’s an infinite sum of negative powers of 10 defined by the pattern before the ellipsis.

          So we have:

          0.101001000100001000001 . . . = 10^-1 + 10^-2 + 10^-3 + 10^-4 +10^-5+ . . .

          Pi, however, is not defined this way. Pi can be defined as twice the solution of the integral from -1 to 1 of the square root of (1-x^2), a function defining a unit semi-circle.

      • मुक्त@lemmy.ml
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        1 day ago

        0.101001000100001000001 . . .

        Might very well be :

        0.101001000100001000001202002000200002000002 …

        Real life, is different from gamified questions asked in student exams.

        • cosecantphi [he/him, they/them]@hexbear.net
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          20 hours ago

          Implicitly defining a number via it’s decimal form typically relies on their being a pattern to follow after the ellipsis. You can define a different number with twos in it, but if you put an ellipsis at the end you’re implying there’s a different pattern to follow for the rest of the decimal expansion, hence your number is not the same number as the one without twos in it.

                • cosecantphi [he/him, they/them]@hexbear.net
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                  14 hours ago

                  Right and the point of defining this number as a non-repeating infinite sequence of 0s and 1s is just to show that non-repetition of digits alone is not sufficient to say a number contains all finite sequences.

                  • मुक्त@lemmy.ml
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                    5 hours ago

                    That trivial point is not the one we (you and me) are contending.

                    The issue is that OP hasn’t actually defined the sequence, just given some properties (which does not lead to any definition or determination of the location of the number/s on the number line, by itself). Assuming that he has defined it, doesn’t change anything as any other commentator can assume something different, which consistent with OP’s post.